math
posted by Anonymous .
At the Natural History museum Paula saw 5 times as many beetles as spiders. She saw 6 more spiders than caterpillars. If Paula saw 50 insects and spiders, how many of each kind did she see?

Start with one variable and then use it to set up your next unknown...and so on. Do you understand?

I guess that was a "no" answer??? OK... let me help a little more. If you'd still like my help. Lets look at setting a variable us for the spiders first. Ok? We will use a letter "S" for the number of Spiders. Lets make a sentence now. She saw: S=spiders; (5xS)= beetles; Caterpillars=(S6);
50 = S + (5xS) + (S6)
50 = S + 5S + S  6
50+6= S + 5S + S
56 = 7S
56/7 = S
8 = S 
Now that we have solved for the 'S' variable, you can plug the value into the other formulas to figure out the number of 'bugs' that were present. Here goes: Spiders is 8, Beetles is 5x8 or 40; Caterpillars are 86 or 2.
Now, double check the answer by making sure they all add up to 50. 40+8+2=50.
I'm so sorry you didn't understand the first part of the question last night. In the future please don't use expletives, no matter how frustrated you may feel. This is a family page here. Thank you.
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