it is 5 digit even number, the digit 3 is in the hundreds place. The value of the digit 4 is 40.the digit 6 stands for 6 ones. The digit in the ten thousands place is twice the digit in the ten place. the value of the digit in the thousands place is 30 time the value of the digit in the hundreds place.
Typo? How can a digit be 30 times any other digit?
To find the 5-digit even number that satisfies the given conditions, let's break down the information provided step by step:
1. The digit 3 is in the hundreds place.
This means our number is _ _ 3 _ _.
2. The value of the digit 4 is 40.
The digit 4 is in the tens place, and its value is given as 40. Since the tens place is 40, we can fill it in: _ 4 3 _ _.
3. The digit 6 stands for 6 ones.
The digit 6 represents the ones place. This means we have 6 as the ones digit: _ 4 3 6 _.
4. The digit in the ten thousands place is twice the digit in the ten place.
Let's call the ten-thousands digit "A" and the tens digit "B". According to the condition, A = 2B. Since we know B is 4, we can substitute it into the equation: A = 2 * 4, which gives us A = 8. Our number now looks like this: 8 4 3 6 _.
5. The value of the digit in the thousands place is 30 times the value of the digit in the hundreds place.
Let's call the thousands digit "C" and the hundreds digit "D". According to the condition, C = 30D. Since we know D is 3, we can substitute it into the equation: C = 30 * 3, which gives us C = 90. Our number now looks like this: 8 4 3 6 9.
Therefore, the 5-digit even number that satisfies all the given conditions is 84369.