Two side of parallelogram are in the ratio 3:4.if its perimeter in 42cm,find its lengths of its side

To find the lengths of the sides of a parallelogram given their ratio and the perimeter, you can follow these steps:

Step 1: Let's represent the lengths of the sides of the parallelogram as 3x and 4x, where x is a common factor.
Step 2: Since the perimeter of a parallelogram is the sum of all its sides, we can write the equation:
2(3x + 4x) = 42
Step 3: Simplify the equation:
2(7x) = 42
14x = 42
Step 4: Divide both sides by 14:
x = 42/14
x = 3
Step 5: Now that we have the value of x, substitute it back into the equation to find the lengths of the sides:
Length of one side = 3x = 3 * 3 = 9 cm
Length of the other side = 4x = 4 * 3 = 12 cm

Therefore, the lengths of the sides of the parallelogram are 9 cm and 12 cm.

42/7 = 6

2L = 3*6 = 18

2W = 4*6 = 24

Since P = 2L + 2W, each side will half of the above values.

We know that a rhombus the diagonal bisect each other at 90 A.C. 24 CM BE 22CM GO 5CM AN 2 AD 2 +O B 2

12 2 +5 2
144+25
169รท1 6 9 13 cm
length of rhombus is 13 cm and