Elizabeth has 45 cents in her pocket.none of the coins are pennies.Make a list of all the combinations that could be in Elizabeth's pocket.
I am so confused. (:V)
I'll start you out. She could have 9 nickels.
Suppose she had some dimes. How many dimes and nickels could she have?
Suppose one is quarter. What other coins might she have?
Where did your name them
No problem, I can help you! Let's break this problem down step by step.
Elizabeth has 45 cents in her pocket, and none of the coins are pennies. We need to figure out all the possible combinations of coins that could add up to 45 cents.
First, let's think about the different types of coins she could have. The most common coins are quarters (25 cents), dimes (10 cents), nickels (5 cents), and pennies (1 cent). However, we know that she doesn't have any pennies, so we can eliminate that option.
Now, let's start by considering the largest coin she could have, which is a quarter (25 cents). Since she can't have any pennies, the remaining amount must be divisible by 25. The closest multiple of 25 less than 45 is 25 itself. So, she could have 1 quarter and 20 cents in other coins.
Next, let's consider if she has any dimes (10 cents). Again, the remaining amount must be divisible by 10 since she doesn't have any pennies. The largest multiple of 10 that is less than 45 (the remaining amount) is 40. So, she could have 1 quarter, 1 dime, and 5 cents (45 - 25 - 10 = 10).
Lastly, let's consider if she has any nickels (5 cents). In this case, the remaining amount must be divisible by 5. The largest multiple of 5 less than 45 (the remaining amount) is 40, but we already accounted for that possibility. Therefore, she can't have any nickels.
Based on these considerations, there are two possible combinations of coins that could be in Elizabeth's pocket:
1. 1 quarter (25 cents) and 20 cents in other coins.
2. 1 quarter (25 cents), 1 dime (10 cents), and 5 cents.
This covers all the possible combinations without using pennies. I hope this explanation helps clarify things for you!