Sum of divisors ofN
You need to clarify your question.
google is your friend. You might want to start here:
https://en.wikipedia.org/wiki/Divisor_function
To find the sum of divisors of a number N, you can follow these steps:
1. Start with the number 1 as a divisor of N.
2. Iterate through all the numbers from 2 to the square root of N. For each number i, if it evenly divides N, add both i and N divided by i to the sum of divisors.
3. Finally, if the square root of N is an integer, you should only add it once to the sum of divisors.
Let's illustrate this with an example. Consider the number N = 12.
- The divisors of 12 are 1, 2, 3, 4, 6, and 12.
- From step 2, we iterate from 2 to the square root of 12, which is approximately 3.46.
- For i = 2, we divide 12 by 2 to get 6. We add both 2 and 6 to the sum, which is currently 9.
- For i = 3, 12 is not divisible by 3, so we continue.
- The sum of divisors is 1 + 2 + 3 + 4 + 6 + 12 = 28.
So, for the number 12, the sum of its divisors is 28.
You can implement this algorithm in various programming languages to calculate the sum of divisors for any given number.