Calculate the concentration of chloride ions in the following solution.
73.28g of sodium chloride in 862. mL of solution.
would it be
73.28g x 2 / 58.44g NaCl = 2.50 mol of Cl
2.50 mol Cl / .862 L = 2.91 M Cl
i meant x 1 mol cl so 1.25 mol cl/.862
Is that concn in M (mols/L). I will assume so.
mols NaCl = 73.28/58.44 = ?
mols Cl = same as mols NaCl
Then M Cl = (mols/0.862L) = ?
To calculate the concentration of chloride ions in the solution, you would first need to calculate the number of moles of sodium chloride (NaCl) in the given mass. Then, you would divide that by the volume of the solution to get the concentration in moles per liter (M).
The molar mass of NaCl is 58.44 g/mol.
First, calculate the moles of NaCl:
Mass of NaCl = 73.28 g
Moles of NaCl = Mass of NaCl / Molar mass of NaCl
= 73.28 g / 58.44 g/mol
= 1.254 mol
Next, convert the volume of the solution to liters:
Volume of solution = 862 mL
= 862 mL / 1000 mL/L
= 0.862 L
Finally, calculate the concentration of chloride ions (Cl-) in the solution:
Concentration (M) = Moles of Cl- / Volume of solution
= 1.254 mol / 0.862 L
≈ 1.455 M Cl-
Therefore, the concentration of chloride ions in the given solution is approximately 1.455 M.