For a deep descent,a scuba diver uses of helium and oxygen with a total pressure of 8.00 atm. If the oxygen has a partial pressure of 1200 mmHg , what is the partial pressure of the helium?

8*760mmHg-1200mmHg=?

To find the partial pressure of helium, we can subtract the partial pressure of oxygen from the total pressure.

1. Convert the partial pressure of oxygen from mmHg to atm:
1200 mmHg * (1 atm / 760 mmHg) = 1.58 atm

2. Subtract the partial pressure of oxygen from the total pressure:
Partial pressure of helium = Total pressure - Partial pressure of oxygen
Partial pressure of helium = 8.00 atm - 1.58 atm = 6.42 atm

Therefore, the partial pressure of helium is 6.42 atm.

To find the partial pressure of helium, we need to convert the oxygen partial pressure from mmHg to atm and subtract it from the total pressure.

First, let's convert the oxygen partial pressure from mmHg to atm:
1 atm = 760 mmHg

So, the oxygen partial pressure in atm is:
1200 mmHg ÷ 760 mmHg/atm = 1.58 atm (rounded to 2 decimal places)

Next, we can subtract the oxygen partial pressure from the total pressure to find the helium partial pressure:
Total pressure - Oxygen partial pressure = Helium partial pressure

8.00 atm - 1.58 atm = 6.42 atm (rounded to 2 decimal places)

Therefore, the partial pressure of helium is 6.42 atm.