What is the smallest of three consecutive integers if
the sum of the smaller two integers is equal to 177 less than four times the largest?
Note: Consecutive integers are integers that come one after the other. For example: -3, -2 and -1 or 14, 15 and 16. Therefore, if the first number is x, the second is x + 1 and the third is x + 2. Each time we add one to the previous integer to get the next consecutive integer.
smallest number ---- x
middle number ------ x+1
larger number --------x+2
x + x+1 = 4(x+2) - 177
2x+1 = 4x+8-117
-2x = -110
x = 55
the smallest is 55
i tried 55 and i got it wrong
Reiny me and madison don't understand this we got it wrong when we tried 55
I even double checked and its wrong i don't know why?
Amy/Brianna/ Joshua/Madison -- please use the same name for your posts.
Correction of subject
According to my solution the 3 numbers are
55, 56, and 57
sum of the first two = 55+56 = 111
117 less than 4 times the larger = 4(57) - 117
= 111
Well, what do you know, it works