An odd number whose thousands digit is twice its hundreds digit
8,431
and many others
To find an odd number whose thousands digit is twice its hundreds digit, we can follow these steps:
1. Let's assign variables to the digits of the number. Let's say the thousands digit is represented by 'A,' and the hundreds digit is represented by 'B.'
2. Since the thousands digit is twice the hundreds digit, we can express this as an equation: A = 2B.
3. Now, we need to consider that the number is odd. In a base-10 number system, the units digit of an odd number is always 1, 3, 5, 7, or 9.
4. Therefore, the last digit of our odd number will be one of the odd digits mentioned above. Let's assign the units digit as 'C.'
5. Combining the variables, our odd number can be represented as ABCC.
6. Now, we can substitute the value of A from step 2 into our representation of the odd number: 2B BCC.
7. Putting it all together, we have the odd number 2B BCC, where B and C can be any digits satisfying the constraints.
For example, if we choose B = 3 and C = 5, the odd number will be 2335.