Find the area of a regular hexagon with the given measurement.
4-inch side
A = sq. in.
Area of a regular hexagon =
[ 3 sqroot ( 3 ) / 2 ] * a ^ 2
Where, a is the side of the hexagon.
A = [ 3 sqroot ( 3 ) / 2 ] * a ^ 2
A = [ 3 sqroot ( 3 ) / 2 ] * 4 ^ 2
A = [ 3 sqroot ( 3 ) / 2 ] * 16
A = [ 3 sqroot ( 3 ) / 2 ] * 2 * 8
A = 3 sqroot ( 3 ) * 8
A = 24 sqroot ( 3 ) in ^ 2
A = 41.56922 in ^ 2
To find the area of a regular hexagon, you can use the formula:
A = (3√3 * s^2) / 2
where A is the area and s is the length of the side of the hexagon.
In this case, the length of the side is given as 4 inches.
Substituting the value in the formula, we have:
A = (3√3 * 4^2) / 2
Simplifying further:
A = (3√3 * 16) / 2
A = 48√3 / 2
A = 24√3 square inches
Therefore, the area of the regular hexagon with a 4-inch side is 24√3 square inches.