a 5kg bomb exploded into two fragments .If one fragment with 3 kg moves in a direction with 5m/s then what is the velocity of the second fragment of mass 2kg
if moving in opposite directions,
3*5 = 2v
To find the velocity of the second fragment, we can use the principle of conservation of momentum. According to this principle, the total momentum before the explosion should be equal to the total momentum after the explosion.
Let's denote the velocity of the second fragment as v2.
First, we calculate the momentum of the first fragment.
Momentum (p) is given by the mass (m) multiplied by the velocity (v).
p1 = m1 * v1
where m1 is the mass of the first fragment (3 kg) and v1 is its velocity (5 m/s).
p1 = 3 kg * 5 m/s
p1 = 15 kg*m/s
Since momentum is conserved, the total momentum after the explosion should also be 15 kg*m/s.
p_total = p1 + p2
where p2 is the momentum of the second fragment.
Next, we can calculate the momentum of the second fragment.
p2 = m2 * v2
where m2 is the mass of the second fragment (2 kg).
Now, we can substitute the values and solve for v2.
p_total = p1 + p2
15 kg*m/s = 15 kg*m/s + 2 kg * v2
Subtracting 15 kg*m/s from both sides:
0 kg*m/s = 2 kg * v2
Dividing both sides by 2 kg:
0 kg*m/s / 2 kg = v2
The velocity of the second fragment is 0 m/s. This means that the second fragment did not move after the explosion.