Which of the following bases could you write an equilibrium expression for?

A. Ba(OH)2
B. KOH
C. NaOH
D. NH3

The answer is NH3

Jesus Bob. smh.

To determine which of the given bases you can write an equilibrium expression for, you need to consider if the base can dissociate or ionize in water to produce hydroxide ions (OH-).

A. Ba(OH)2: This compound dissociates in water to form Ba2+ cations and 2 OH- anions, so you can write an equilibrium expression for it.

B. KOH: KOH dissociates in water to form K+ cations and OH- anions, so you can also write an equilibrium expression for it.

C. NaOH: Similar to KOH, NaOH dissociates in water to form Na+ cations and OH- anions, so you can write an equilibrium expression for it as well.

D. NH3: NH3 is not a base that produces OH- ions in water. Instead, it acts as a weak base and reacts with water to produce ammonium ion (NH4+) and hydroxide ion (OH-). Since it doesn't directly produce OH- ions, you cannot write an equilibrium expression for NH3.

Therefore, the correct bases for which you can write an equilibrium expression are A. Ba(OH)2, B. KOH, and C. NaOH.

I can write a Keq for all of them.