What is the equilibrium expression for the change when iron(II) chloride dissolves?

FeCl2(s) Fe2+(aq) + 2Cl-(aq)

K= (FE^2+)(Cl^-aq)^2

The equilibrium expression for the dissolution of iron(II) chloride is as follows:

[Fe2+][Cl-]^2

This expression represents the equilibrium concentrations of the iron(II) ions (Fe2+) and chloride ions (Cl-) in solution. The square bracket notation represents the concentration of each ion.

To determine the equilibrium expression for the change when iron(II) chloride (FeCl2) dissolves, we need to look at the balanced chemical equation for the dissolution:

FeCl2(s) ⇌ Fe2+(aq) + 2Cl-(aq)

The equilibrium expression is a mathematical representation that summarizes the concentrations of the species involved in the reaction at equilibrium. It is written in terms of the products divided by the reactants, with each species raised to the power of its coefficient in the balanced equation.

In this case, the equilibrium expression for the dissolution of iron(II) chloride is:

\[ [Fe^{2+}][Cl^-]^2 \]

The square brackets indicate the concentration of each ion in mol/L. The concentration of Fe2+ is represented by [Fe2+] and the concentration of Cl- is represented by [Cl-]. Since there are two chloride ions formed for every one Fe2+ ion, the concentration of Cl- is raised to the power of 2 in the equilibrium expression.

Note that the solid FeCl2 is not included in the expression because it is in a pure solid state and does not contribute to the equilibrium.

Keq = (Fe^2+aq)(Cl^-aq)^2/(FeCl2). Some may argue that the denominator of FeCl2 should not appear; however, by definition it is 1 and like to put it in.