A particle is traveling counterclockwise in a circle of radius

r = 2.30 m.
At some instant in time, the particle is located by the angular coordinate
α = 24.0°,
the total acceleration has a magnitude of
a = 15.0 m/s2
and is directed at an angle
β = 20.0°
with respect to the radial coordinate. Determine (a) position vector (b) velocity (c) total acceleration

(a) To determine the position vector, we need to convert the given angular coordinate α = 24.0° into radians.

1 radian = 180°/π

So, α in radians = 24.0° * (π/180°) = 0.4189 radians

The position vector, denoted as r, can be calculated using the formula:

r = r * cos(α) i + r * sin(α) j

where r is the radius and i, j are the unit vectors in the x and y directions respectively.

Given r = 2.30 m and α = 0.4189 radians:

r = 2.30 * cos(0.4189) i + 2.30 * sin(0.4189) j

Evaluating this expression will give us the position vector.

(b) To determine the velocity vector, we need to find the derivative of the position vector with respect to time.

v = dr/dt

Differentiating the position vector equation from part (a) with respect to time will give us the velocity vector.

(c) To determine the total acceleration vector, we need to consider two components: radial acceleration (ar) and tangential acceleration (at).

The magnitude of the total acceleration, a = 15.0 m/s^2, can be decomposed into radial and tangential components using the following trigonometric relationships:

ar = a * cos(β)
at = a * sin(β)

Given β = 20.0°, we can convert it into radians:

β in radians = 20.0° * (π/180°) = 0.3491 radians

Substituting the values into the equations, we can find the radial and tangential accelerations.

The total acceleration vector, denoted as A, is the vector sum of the radial and tangential acceleration vectors:

A = ar i + at j

Substituting the obtained values for ar and at will give us the total acceleration vector.

To determine the position vector, velocity, and total acceleration of the particle, we can use the concepts of circular motion and vector addition.

(a) Position Vector:
The position vector represents the displacement of the particle from the origin to its current location. It can be calculated using the radius and angular coordinate.

To find the position vector, we use the formula:

r = R * cos(α) i + R * sin(α) j

where R is the radius of the circle, α is the angular coordinate, and i and j are the unit vectors in the x and y directions, respectively.

Substituting the given values, we have:

r = 2.30 m * cos(24.0°) i + 2.30 m * sin(24.0°) j

Using a calculator or trigonometric functions, we can calculate the cosine and sine values and substitute them into the equation to find the position vector.

(b) Velocity:
To find the velocity vector, we differentiate the position vector with respect to time. Since the particle is moving in a circle at a constant speed and counterclockwise, the velocity vector is perpendicular to the position vector and points tangentially to the circle.

The magnitude of the velocity vector is given by v = R * ω, where ω is the angular velocity (rate of change of angular position with respect to time).

To find the direction of the velocity vector, we rotate the position vector by 90 degrees counterclockwise (since it is perpendicular).

Therefore, the velocity vector v = -R * ω * sin(α) i + R * ω * cos(α) j

(c) Total Acceleration:
To find the total acceleration vector, we differentiate the velocity vector with respect to time. The total acceleration consists of two components: tangential acceleration (due to change in speed) and radial acceleration (due to change in direction).

The tangential acceleration can be calculated using the formula:

at = R * α

where α is the angular acceleration (rate of change of angular velocity with respect to time).

The radial acceleration can be calculated using the formula:

ar = R * ω^2

The magnitude of the total acceleration is given by a = √(at^2 + ar^2), and the direction can be determined from the angle β with respect to the radial coordinate.

Therefore, the total acceleration vector a = -at * sin(α) i + at * cos(α) j + ar * sin(β) i + ar * cos(β) j

Substituting the given values, we can calculate the tangential acceleration, radial acceleration, and substitute them into the equation to find the total acceleration vector.

Note: Make sure to convert all angles to radians when using trigonometric functions and double-check all formulas and calculations for accuracy.