How would you set up an equation to solve this problem?
A clown weighs 60 lbs more than a trapeze artist. The trapeze artist weighs two thirds as much as the clown. How much does each weigh?
Choices for the weight of the trapeze artist are: 110, 120, 125
c = t+60
t = 2/3 c
or,
t = 2/3 (t+60)
Thanks how about this one?
Western State College is 18 years older than southern state. Western is also 2.5 times as old as southern state. How old is each?
choices for southern state are 12, 14, and 18
huh? This is exactly like the last one; just use different numbers.
What do you get?
W=2.5S
W = S + 18
2.5S=S + 18?
yes.
To set up an equation to solve this problem, we can define a variable to represent the weight of the trapeze artist. Let's call it "x."
According to the problem, the clown weighs 60 lbs more than the trapeze artist, which means the clown's weight is x + 60. Additionally, it is mentioned that the trapeze artist weighs two-thirds as much as the clown, so we can write this as (2/3)(x + 60).
Now, we can set up an equation using the information given. According to the problem, the trapeze artist's weight is one of the choices given: 110, 120, or 125.
Case 1: If the weight of the trapeze artist is 110 lbs, we can express this mathematically as:
x = 110
Case 2: If the weight of the trapeze artist is 120 lbs, we can express this mathematically as:
x = 120
Case 3: If the weight of the trapeze artist is 125 lbs, we can express this mathematically as:
x = 125
By solving these equations, we can determine the weight of the trapeze artist and the clown.