Math
posted by Nye
Let A(2,3) be a fixed point. A point P moves such that PA is equal to the distance of P from the yaxis. Find the equation of the locus of P
PA2 = (xx1)^2 + (yy1)^2 +???
= (x2)^2 + (y3)^2 +???
I tried solving it using the distance formula but I'm still confused because I am given only one point A (2,3) coordinate. I searched all blogs on google but couldn't find a solved problem similar to this. Please help!

Steve
Ths distance of (x,y) from the yaxis is just x. So,
√((x2)^2 + (y3)^2) = x
(x2)^2 + (y3)^2 = x^2
x^24x+4 + (y3)^2 = x^2
(y3)^2 = 4x4
(y3)^2 = 4(x1)
as I showed using the properties of parabolas
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