The sum of five consecutive numbers is 645. Find the numbers.
Thank you
To find the consecutive numbers whose sum is 645, we can call the first number in the sequence "x".
The sum of five consecutive numbers can be found by adding the numbers together: x + (x+1) + (x+2) + (x+3) + (x+4) = 645.
Combining like terms, we have: 5x + 10 = 645.
Subtracting 10 from both sides, we have: 5x = 635.
To isolate "x", we divide both sides by 5: x = 635/5.
Simplifying, we get: x = 127.
Therefore, the five consecutive numbers are 127, 128, 129, 130, and 131.
To solve this problem, we need to use algebraic equations. Let's denote the first number by "x".
Since we are given five consecutive numbers, the other four numbers can be represented as x+1, x+2, x+3, and x+4.
The sum of all five numbers is given to be 645:
x + (x+1) + (x+2) + (x+3) + (x+4) = 645
Now, we can simplify the equation:
5x + 10 = 645
Next, we subtract 10 from both sides of the equation:
5x = 635
To isolate x, we divide both sides of the equation by 5:
x = 635/5
x = 127
Therefore, the five consecutive numbers are: 127, 128, 129, 130, and 131.
IF it were three
n-1 + n + n+1 = 645
3 n = 645
n = 2 1 5
Now you do it for 5