PhysicsA race car travels northward on a straight, level track at a constant speed travels 0.755 km in 18.0 s. The return trip over the same track is made in 23.0 s.

(a) What is the average velocity of the car in m/s for the first leg of the run?
41.94

Correct: Your answer is correct. .
m/s
What is the average velocity for the total trip?

To find the average velocity for the total trip, we need to consider both the first and second legs of the run.

The average velocity is defined as the total displacement divided by the total time taken. In this case, the total displacement is the sum of the displacements for the first and second legs, and the total time taken is the sum of the times for the first and second legs.

First, let's find the displacement for each leg of the run. The displacement is the change in position, which is the difference between the initial and final positions. Since the race car is traveling north on a straight track on both legs, the displacement will be positive for both.

For the first leg, the displacement is the distance traveled, which is 0.755 km. However, we need to convert this to meters, since the average velocity should be in m/s. 1 km is equal to 1000 m, so the displacement for the first leg is 0.755 km * 1000 m/km = 755 m.

For the second leg, the displacement is also the distance traveled, which is again 0.755 km. Therefore, the displacement for the second leg is also 755 m.

Next, let's find the total time taken for the trip. The total time is the sum of the times for the first and second legs, which are given as 18.0 s and 23.0 s, respectively. Therefore, the total time taken for the trip is 18.0 s + 23.0 s = 41.0 s.

Finally, let's calculate the average velocity for the total trip. The average velocity is the sum of the displacements divided by the total time taken. Therefore, the average velocity is (755 m + 755 m) / 41.0 s = 1510 m / 41.0 s = 36.83 m/s.

So, the average velocity for the total trip is 36.83 m/s.