Calculate the volume of 1.0 M CuSO4 stock solution you should use to make 100 mL of a 0.010 m CuSO4 solution.

1.0 ml

1 mL

Well, let's dive into chemistry with a laugh! To calculate the volume of the 1.0 M CuSO4 stock solution you should use, we need to perform a simple calculation.

First, let's start by figuring out the moles of CuSO4 needed in the 100 mL solution. Since we want a 0.010 m CuSO4 solution, we multiply this molarity by the desired volume (100 mL) to get the moles:

Moles = Molarity × Volume
Moles = 0.010 mol/L × 0.100 L
Moles = 0.001 mol

Now, we can use the concentration of the stock solution to determine the volume needed. Being a 1.0 M CuSO4 solution, the concentration tells us that there is 1 mole of CuSO4 per liter of solution. To find the volume required for 0.001 moles:

Volume = Moles / Concentration
Volume = 0.001 mol / 1.0 mol/L
Volume = 0.001 L or 1 mL

So, to make 100 mL of a 0.010 m CuSO4 solution, you would need 1 mL of the 1.0 M CuSO4 stock solution.

Remember, chemistry can sometimes be confusing, but with a touch of humor, it's always a catalyst for fun!

To calculate the volume of the 1.0 M CuSO4 stock solution you should use to make 100 mL of a 0.010 M CuSO4 solution, you can use the equation:

C1V1 = C2V2

where C1 is the concentration of the stock solution, V1 is the volume of the stock solution, C2 is the desired concentration of the final solution, and V2 is the desired volume of the final solution.

In this case, the concentration of the stock solution (C1) is 1.0 M, the desired concentration of the final solution (C2) is 0.010 M, and the desired volume of the final solution (V2) is 100 mL.

Rearranging the equation to solve for V1:

V1 = (C2V2) / C1

Substituting the given values:

V1 = (0.010 M * 100 mL) / 1.0 M

Calculating the volume:

V1 = 0.10 mL

Therefore, you would need to use 0.10 mL of the 1.0 M CuSO4 stock solution to make 100 mL of a 0.010 M CuSO4 solution.

Did you know there is a difference between 0.010 m and 0.010 M. I will assume you meant 0.010 M.

mL1 x M1 = mL2 x M2
100 x 0.01 = mL2 x 1.0
Solve for mL2 needed. Use that amount and make to 100 mL in a volumetric flask, mix thoroughly, stopper.