find
lim 1-2x / 1+6x
x -> infinity
find
lim [ x / ((3+x)^2) -5]
x -> infinity
first:
multipy numerator AND denominator by 1/x
It becomes
lim (-2/6) or -1/3
second: the first term will go to zero, so the lim is -5
lim 1-2x / 1+6x
x -> infinity
find
lim [ x / ((3+x)^2) -5]
x -> infinity
multipy numerator AND denominator by 1/x
It becomes
lim (-2/6) or -1/3
second: the first term will go to zero, so the lim is -5