The length of a rectangle is twice its width. The perimeter of the rectangle is 126ft.
Length = 2* width
Let length be l and w be the width
Then
2(l+w)=126
2(3w)=126
W=126/6
Find out what you want to find.
And please type the full question. That one seems to be just a statement.
l = length
w = width
P = perimeter
l = 2 w
P = 2 ( l + w ) = 126
2 ( 2 w + w ) = 126
2 * 3 w = 126
6 w = 126
w = 126 / 6 = 21 ft
l = 2 w = 2 * 21 = 42 ft
To find the length and width of the rectangle, we can use the given information that the length is twice the width and the perimeter of the rectangle is 126 feet.
Let's assume that the width of the rectangle is represented by the variable "w".
According to the given information, the length of the rectangle is twice the width, so it would be represented by the expression "2w".
The formula for the perimeter of a rectangle is: perimeter = 2(length + width).
Using this formula, we can substitute the given values and unknowns:
126 = 2(2w + w)
Now, let's solve this equation to find the value of "w":
126 = 2(3w)
Divide both sides of the equation by 2:
63 = 3w
Divide both sides of the equation by 3:
21 = w
Therefore, the width of the rectangle is 21 feet.
To find the length of the rectangle, we can substitute the value of "w" into the expression for the length:
Length = 2w = 2 * 21 = 42
So, the length of the rectangle is 42 feet.
In summary, the width of the rectangle is 21 feet and the length is 42 feet.