calculate the mass of ice required to lower the temperature of 300 gm of water at 40degree celcius to water at0 degree celcius.

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150 gram

To calculate the mass of ice required to lower the temperature of water, we need to use the formula:

Q = m * c * ΔT

Where:
Q = Heat energy transferred
m = Mass
c = Specific heat capacity
ΔT = Change in temperature

In this case, we want to find the mass of ice (m) needed to lower the temperature of 300 grams of water from 40 degrees Celsius to 0 degrees Celsius.

First, we need to calculate the heat energy (Q) required to lower the temperature of water. We can use the specific heat capacity of water, which is 4.18 J/g°C, and the formula:

Q = m * c * ΔT

Substituting the given values:
Q = 300 g * 4.18 J/g°C * (40°C - 0°C)
Q = 300 g * 4.18 J/g°C * 40°C
Q = 50,160 J

Next, we need to calculate the heat energy (Q') released by the ice as it changes from 0°C to its melting point, which is 0°C. We can use the specific heat capacity of ice, which is 2.09 J/g°C, and the formula:

Q' = m' * c' * ΔT'

Substituting the given values:
Q' = m' * 2.09 J/g°C * (0°C - 0°C)
Q' = 0 J

Since there is no change in temperature during the phase change, the heat energy (Q') released is zero.

Now, we can equate the heat energy required (Q) with the heat energy released (Q') to find the mass of ice (m'):

Q = Q'
50,160 J = m' * 0 J/g
m' = 50,160 J / 0 J/g
m' = undefined

Since dividing by zero is undefined, it means that there is no mass of ice required to lower the temperature of 300 grams of water from 40 degrees Celsius to 0 degrees Celsius.