Angelina goes to the library every 7 days.She goes to the market every 4 days.Today August 1, Angelina goes to both the library and the market.How many more time will she go to both places on the same day for the reminder of the year?
Multiples:
library: 7, 14, 21, 28, 35, 42
market: 4, 8, 12, 16, 20, 24, 28, 32
Since the least common multiple is 28, she must go to the library and the market on each 28th day.
Take it from there.
Angelina will go every 28 days.
To find out how many more times Angelina will go to both the library and the market on the same day for the remainder of the year, we need to calculate the number of days remaining in the year from August 1.
1. Determine the number of days remaining in the year starting from August 1:
- August has 31 days
- There are 365 days in a year
- Days remaining = 365 - 31 (August) - 1 (August 1) = 333 days
2. Calculate the least common multiple (LCM) of 7 and 4 to determine how often Angelina will go to both places on the same day:
- LCM(7, 4) = 28
3. Divide the number of days remaining by the LCM to find the number of times Angelina will go to both places on the same day:
- Number of times = 333 / 28 ≈ 11.892
Since we cannot have a fraction of a day, we can conclude that Angelina will go to both the library and the market on the same day approximately 11 more times for the remainder of the year.