Write the first five terms of the sequence. (Assume that n begins with 1.) a (subtext)n =−7n+8
a. 8, 1, –6, –13, –20
b. 1, –6, –13, –20, –27
c. 1, –14, –21, –28, –35
d. 1,9,17,25,33
e. –15, –22, –36, –36, –43
when n=1, A1 = -7*1+8 = -7+8 = 1
now just start subtracting 7 again and again.
To find the first five terms of the sequence, we will substitute n = 1, 2, 3, 4, and 5 into the formula aₙ = -7n + 8.
For n = 1, we have:
a₁ = -7(1) + 8
a₁ = -7 + 8
a₁ = 1
For n = 2, we have:
a₂ = -7(2) + 8
a₂ = -14 + 8
a₂ = -6
For n = 3, we have:
a₃ = -7(3) + 8
a₃ = -21 + 8
a₃ = -13
For n = 4, we have:
a₄ = -7(4) + 8
a₄ = -28 + 8
a₄ = -20
For n = 5, we have:
a₅ = -7(5) + 8
a₅ = -35 + 8
a₅ = -27
Therefore, the first five terms of the sequence are 1, -6, -13, -20, and -27.
The correct answer is option b. 1, -6, -13, -20, -27.