How many metric tons (1 metric ton = 10^3 kg) of H2O fell on a city? (1cm^3 of H2O has a mass of 1g = 10^-3 kg)
Thus far I have:
10^-3 Kg x (1 metric ton/10^3)
but I don't understand the significance of adding 1 cm^3 to the problem.
you need to know how many cm of rain fell and the area of the city.
1 cm^3 = 10^-3 kg = 10^-6 tons
need depth of water in cm * area of city in cm^2 to get volume in cm^3
multiply that by 10^-6 to get tons.
To find out how many metric tons of water fell on a city, we need to know the volume of water that fell. The information about 1 cm^3 of water having a mass of 1g is provided to help determine the volume.
By using the given conversion that 1 cm^3 of water has a mass of 1g (which is equal to 10^-3 kg), we can convert the volume of water to kilograms. Once we have the mass in kilograms, we can then convert it to metric tons using the conversion that 1 metric ton is equal to 10^3 kilograms.
So, to calculate the mass of the water in kilograms, we multiply the volume in cubic centimeters by the mass of water per cubic centimeter:
Volume of water in cm^3 x Mass of water per cm^3 = Mass of water in kg
Once we have the mass of water in kilograms, we can convert it to metric tons by dividing it by 10^3:
Mass of water in kg / 10^3 = Mass of water in metric tons
By following these steps, you can determine the amount of water that fell in metric tons based on the given information.