How do I solve this

(3x^4y)^3

3^3 = 27

(x^4)^3 = x^12

so
27 x^12 y^3

Thanks

You are welcome.

To solve the expression (3x^4y)^3, we need to apply the exponent rule of raising a power to another power. Here's how you can do it step by step:

Step 1: Distribute the exponent 3 to both the base 3x^4y.

(3x^4y)^3 = 3^3 * (x^4)^3 * y^3

Step 2: Simplify the exponent of the base 3.

3^3 = 27

(27) * (x^4)^3 * y^3

Step 3: Simplify the exponent of the base x^4.

(x^4)^3 = x^(4*3) = x^12

27 * x^12 * y^3

Step 4: Simplify the expression further.

The final answer is 27x^12y^3.

So, (3x^4y)^3 simplifies to 27x^12y^3.