THE 14TH TERM OF AP IS 96 WHILE THE 25TH TERM IS 173 FIND THE
A.19TH TERM
B.SUM OF 13TH AND 56TH TERM
173=a+24d
96=a+13d
77=11d
d=7
96=a+13×7
96=a+91
a=5
19th term = a+18d
5+18×7
=131
The14th term of an ap is 96 while the 25th term is 173 find the (a)the19th term (b)sum of 13th and 5th term (c)product of
What about b the sum of 13th and 56th term
LOL, yes :) good
TN=A+(N-1)D
T19=5+(19-1)7=5+18(7)
=15+126=T19=131
Tn=a+(n-1)d
93=a+(14-1)d
96=a+13d---eqn(i)
173=a+(25-1)d
173=a+24d---eqn(ii)
a+13d=96
a+24d=173
11d=77
d=7 a+13(7)=96
a+91=96
a=96-1
a=5
(a) tn=5+(19-1)7
T19=5+(18)7
T19=5+126
T19=131
http://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html
Xn = a +(n-1)d
96 = a + 13 d
173 = a + 24 d
---------------
-77 = -11 d
d = 7
then a = 96 - 13*7 = 5
so
X19 = 5 + 18*7 = 131 etc