25.0 mL of an H3BO3 solution were titrated with 29.15 mL of a 0.205 M LiOH solution to reach the equivalence point. what is the molarity of the H3BO3 solution?
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To determine the molarity of the H3BO3 solution, we can use the concept of stoichiometry and the balanced chemical equation of the reaction between H3BO3 and LiOH.
The balanced chemical equation for the reaction is:
H3BO3 + 3LiOH → Li3BO3 + 3H2O
From the balanced equation, we can see that the ratio between H3BO3 and LiOH is 1:3. This means that for every 1 mole of H3BO3, we need 3 moles of LiOH to react.
First, let's calculate the number of moles of LiOH that reacted:
moles of LiOH = volume of LiOH solution (in L) × molarity of LiOH solution
Given:
volume of LiOH solution = 29.15 mL = 0.02915 L
molarity of LiOH solution = 0.205 M
moles of LiOH = 0.02915 L × 0.205 M
moles of LiOH = 0.00597475 mol
Since the ratio between H3BO3 and LiOH is 1:3, the number of moles of H3BO3 is one-third of the moles of LiOH that reacted:
moles of H3BO3 = (1/3) × 0.00597475 mol
moles of H3BO3 = 0.00199158 mol
Next, we need to determine the molarity of the H3BO3 solution.
molarity of H3BO3 solution = moles of H3BO3 / volume of H3BO3 solution (in L)
Given:
volume of H3BO3 solution = 25.0 mL = 0.0250 L
molarity of H3BO3 solution = 0.00199158 mol / 0.0250 L
molarity of H3BO3 solution = 0.0797 M
Therefore, the molarity of the H3BO3 solution is approximately 0.0797 M.
To find the molarity of the H3BO3 solution, we can use the concept of stoichiometry and the balanced chemical equation between H3BO3 and LiOH.
The balanced chemical equation for the reaction between H3BO3 and LiOH is:
H3BO3 + 3LiOH -> Li3BO3 + 3H2O
From the equation, we can see that the mole ratio between H3BO3 and LiOH is 1:3. This means that for every 1 mole of H3BO3, we need 3 moles of LiOH to react.
Given that 25.0 mL of H3BO3 solution were titrated, we need to calculate the amount in moles of H3BO3 used.
To do this, we can use the following formula:
Amount of substance (in moles) = (volume (in mL) × Molarity) / 1000
Using the given values, we can calculate the amount of moles of H3BO3 as follows:
Amount of substance of H3BO3 = (25.0 mL × Molarity of H3BO3) / 1000
Next, we can set up an equation using the stoichiometric ratio:
Amount of moles of H3BO3 = 3 × amount of moles of LiOH
Therefore:
(25.0 mL × Molarity of H3BO3) / 1000 = 3 × (29.15 mL × 0.205 M LiOH) / 1000
Now we can solve for the Molarity of H3BO3:
Molarity of H3BO3 = [3 × (29.15 mL × 0.205 M LiOH) / 1000] / (25.0 mL / 1000)
Simplifying the equation:
Molarity of H3BO3 = [3 × 29.15 × 0.205] / 25.0
Molarity of H3BO3 = 1.517 M
Therefore, the molarity of the H3BO3 solution is approximately 1.517 M.
H₃BO₃ is triprotic (3 H⁺ per molecule)
29.15 * .025 = M * 3 * 25.0