A shopkeeper mixes two types of milk costing rs 25per litre and rs 30per litre. if he sells 60litres of mixture for rs 1600, find the quantity of each type of milk.
If there are x liters of 25/L then we have the value of the milk as
25x + 30(60-x) = 1600
To solve this problem, we can use the method of mixtures. Let's assume that the quantity of milk costing Rs 25 per litre is x litres, and the quantity of milk costing Rs 30 per litre is y litres.
We can set up two equations to represent the given information:
Equation 1: x + y = 60 (since the total quantity of milk sold is 60 litres)
Equation 2: (25x + 30y) = 1600 (since the total cost of the mixture is Rs 1600)
Now, we can solve these equations simultaneously to find the values of x and y.
Multiply Equation 1 by 25 to eliminate x:
25x + 25y = 25 * 60
25x + 30y = 1600
Subtract the two equations:
(25x + 30y) - (25x + 25y) = 1600 - (25 * 60)
5y = 1600 - 1500
5y = 100
y = 100 / 5
y = 20
Substitute the value of y back into Equation 1:
x + 20 = 60
x = 60 - 20
x = 40
Therefore, the quantity of milk costing Rs 25 per litre is 40 litres, and the quantity of milk costing Rs 30 per litre is 20 litres.