How many moles of chloride ions are in 0.04dm^3 of 0.45M calcium chloride CaCl2
a dm^3 is a liter
two chloride ions per calcium chloride molecule
.04 * .45 * 2
To find the number of moles of chloride ions in a solution of calcium chloride, we need to use the concentration and volume of the solution.
Step 1: Write down the balanced chemical equation for dissolving calcium chloride in water:
CaCl2 → Ca2+ + 2Cl-
This equation shows that for every one formula unit of calcium chloride (CaCl2), we get two moles of chloride ions (2Cl-).
Step 2: Calculate the moles of calcium chloride (CaCl2) in the given solution:
Moles of CaCl2 = concentration of CaCl2 × volume of solution
= 0.45 mol/dm^3 × 0.04 dm^3
= 0.018 moles of CaCl2
Step 3: Calculate the moles of chloride ions (Cl-) using the mole ratio from the balanced chemical equation:
Moles of Cl- = 2 × moles of CaCl2
= 2 × 0.018 moles
= 0.036 moles
Therefore, there are 0.036 moles of chloride ions in 0.04 dm^3 of 0.45M calcium chloride solution.