Math
posted by Stephen .
Context: The function v(t) represents the velocity of a particle moving along a horizontal line at any time, t, greater than or equal to zero. If the velocity is positive, the particle moves to the right. If the velocity is negative, the particle is moving to the left.
The question: A particle has a velocity function v(t)=Asin(B(tC))+D, with the minimum velocity at the point (1, 4) and the maximum velocity at the point (4, 2). Evaluate the constants A,B, C, and D and write the complete function.

v = A sin(B(tC))+D
max v = D+A = 2
min v = DA = 4
So, D = 1 and A = 3
v = 3sin(B(tC))1
max of sinθ occurs at θ = π/2
max of sinθ occurs at θ = 3π/2
so, see what you can do with that, the way I git A and D above.
Recall that the period of sin(kt) is 2π/k 
What I ended up getting was
v(t)=3 sin( pi/3 (t ((4pi/2)))) 1
so B= pi/3 and C=4–pi/2 
I'll have to see where you went wrong. Too bad you didn't show your work, like me. wolframalpha says you are off:
http://www.wolframalpha.com/input/?i=3+sin(+pi%2F3+(t+((4pi%2F2))))+1
Respond to this Question
Similar Questions

Calc I
A particle moves at varying velocity along a line and s= f(t) represents the particle's distance from a point as a function of time, t. sketch a graph for f if the average velocity of the particle between t=2 and t=6 is the same as … 
Calculus (Answer Check)
Are my answers right? If they are wrong you don't have to tell me how to do it its okay =) A particle starts at time t=0 and moves along the xaxis so that its position at any time t(greater or equal to) 0 is given by x(t)=(t1)^3 
Calculus
a particle starts at time t = 0 and moves along the x axis so that its position at any time t>= 0 is given by x(t) = ((t1)^3)(2t3) a.find the velocity of the particle at any time t>= 0 b. for what values of t is the velocity … 
Math: Calculus
The velocity function is v(t)= t^25t+ 4 for a particle moving along a line. The position function s(t) is an antiderivative of the velocity function. Find the displacement, s(6)  s(3), by the particle during the time interval [3,6]. 
Calculus
A particle moves at varying velocity along a line and s=f(t) represents the particle's distance from a point as a function of time, t. Sketch a possible graph for f if the average velocity of the particle between t=2 and t=6 is the … 
Calculus AB
A particle is moving along the xaxis so that at time t its acceleration is a(t)=ðcos(ðt) At time t=1/2, the velocity v of the particle is 1/2. Find the velocity of the particle at any time t. I think I got that right, as sinðt … 
math
a particle starts at time t = 0 and moves along the x  axis so that its position at any time t is greater than or equal to zero is given x(t) = (t1)^3(2t3) A. Find the velocity of the particle at any time t greater than or equal … 
Physics
A particle starts from the origin at t = 0 and moves along the positive x axis. A graph of the velocity of the particle as a function of the time is shown in the figure; the vaxis scale is set by vs = 7.0 m/s. (a) What is the coordinate … 
Calculus
The Question: A particle moves along the Xaxis so that at time t > or equal to 0 its position is given by x(t) = cos(√t). What is the velocity of the particle at the first instance the particle is at the origin? 
Physics
The velocity graph of a particle moving along the xaxis is shown. The particle has zero velocity at t=0.00s and reaches a maximum velocity, vmax, after a total elapsed time, t total. If the initial position of the particle is x0 =6.22m, …