Write the net ionic equation for HClO4(aq) + NaOH(aq) --> H2O (l) + NaClO4(aq).
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To write the net ionic equation, we start by writing the balanced equation for the given reaction:
HClO4(aq) + NaOH(aq) → H2O(l) + NaClO4(aq)
Next, we need to identify the species that are present in the reaction as ions in the solution. These are known as the "spectator ions" because they do not undergo any chemical change.
The complete ionic equation for the reaction would be:
H+(aq) + ClO4-(aq) + Na+(aq) + OH-(aq) → H2O(l) + Na+(aq) + ClO4-(aq)
Now, we can eliminate the spectator ions from both sides of the equation, as they are present on both sides:
H+(aq) + OH-(aq) → H2O(l)
This is the net ionic equation for the given reaction. It shows only the species that are directly involved in the chemical change, which in this case, is the formation of water from the combination of H+ and OH-.
To find the net ionic equation, we need to write out the balanced molecular equation first, and then convert it to the ionic equation. Finally, we can cancel out the spectator ions to obtain the net ionic equation.
1. Write the balanced molecular equation:
HClO4(aq) + NaOH(aq) → H2O(l) + NaClO4(aq)
2. Convert to the ionic equation by separating the aqueous compounds into their respective ions:
H+(aq) + ClO4-(aq) + Na+(aq) + OH-(aq) → H2O(l) + Na+(aq) + ClO4-(aq)
3. Cancel out the spectator ions (ions that appear on both sides of the equation):
H+(aq) + OH-(aq) → H2O(l)
The net ionic equation is: H+(aq) + OH-(aq) → H2O(l)