a 0.1 gm sample requires 20.5 ml B for reaction. the B was standardized by titrating 25 ml of a 0.1M CaCl2 solution, requiring 30 ml B. calculate the percent Al2O3
To calculate the percent Al2O3, we need to know the amount of Al2O3 in the reaction and the amount of Al2O3 in the sample.
Let's start by calculating the amount of Al2O3 in the titration of CaCl2 solution.
Given:
- Volume of B used in the titration of CaCl2 solution (B1) = 30 mL
- Concentration of CaCl2 solution (C1) = 0.1 M
- Volume of CaCl2 solution used (V1) = 25 mL
We can calculate the moles of CaCl2 using the formula:
Moles of CaCl2 = Concentration of CaCl2 x Volume of CaCl2 solution
= C1 x V1
Substituting the given values, we have:
Moles of CaCl2 = (0.1 M) x (0.025 L)
= 0.0025 moles
Since the balanced chemical equation for the reaction between CaCl2 and B is 1:1, the moles of Al2O3 produced in the reaction will also be 0.0025 moles.
Now, let's calculate the amount of Al2O3 in the 0.1 gm sample using the given data:
Given:
- Mass of the sample = 0.1 gm
- Volume of B used in the sample reaction = 20.5 mL
The molar mass of Al2O3 is 101.96 g/mol. We can calculate the moles of Al2O3 in the sample using the formula:
Moles of Al2O3 = Mass of the sample / Molar mass of Al2O3
= 0.1 g / 101.96 g/mol
Now, we can calculate the percent Al2O3 in the sample using the formula:
Percent Al2O3 = (Moles of Al2O3 in sample / Moles of Al2O3 in the titration) x 100
Substituting the calculated values, we have:
Percent Al2O3 = [(0.1 g / 101.96 g/mol) / 0.0025 moles] x 100
Now, you can plug in the values and calculate the percent Al2O3 in the sample.