Plse Help how do you obtain the maximum value and minimum value of a quadratic equation like for , 1/11+8x-2x^2
The graph of a quadratic is a parabola.
A parabola has a max or min at the vertex. If the coefficient of x^2 is + it has a min (holds water), Otherwise a max.
so find the vertex
if y = ax^2 +bx +c
then to find zeros you do
x = [ -b +/- sqrt(b^2-2ac) ]/2a
symmetry (center of the cup shape) is at x = -b/2a
so that is the x value of the vertex and use that x to find y of the vertex.