How to prepare 10mM NaH2PO4?
To prepare a 10mM NaH2PO4 solution, you would need to know the molecular weight of NaH2PO4 and the desired volume of the final solution. Here's a step-by-step method to prepare it:
1. Determine the molecular weight of NaH2PO4. Sodium (Na) has an atomic weight of 22.99 g/mol, hydrogen (H) has an atomic weight of 1.01 g/mol, and phosphorus (P) has an atomic weight of 30.97 g/mol. Oxygen (O) has an atomic weight of 16.00 g/mol. Adding these up, the molecular weight of NaH2PO4 is 119.98 g/mol.
2. Calculate the amount of NaH2PO4 needed based on the desired concentration and volume. The formula to calculate the amount of solute (NaH2PO4) needed is:
Mass (g) = (Concentration (mol/L) x Molecular Weight (g/mol) x Volume (L))
Since the concentration is given as 10mM, which is equivalent to 0.01 mol/L, and the desired final volume is not specified, I will assume a volume of 1 liter for the calculations.
Mass (g) = (0.01 mol/L) x (119.98 g/mol) x (1 L)
Mass (g) = 1.1998 grams
So, to prepare a 10mM NaH2PO4 solution with a final volume of 1 liter, you will need approximately 1.1998 grams of NaH2PO4.
3. Weigh out the calculated amount of NaH2PO4 using a balance (scale) that can measure to the nearest milligram (0.001 grams).
4. Dissolve the weighed NaH2PO4 in a small volume of deionized water or a suitable solvent to ensure complete dissolution.
5. Transfer the dissolved NaH2PO4 solution to a volumetric flask or a container where you can accurately measure the final volume.
6. Add deionized water to the flask and bring the total volume up to 1 liter. Ensure that it is thoroughly mixed to obtain a homogenous solution.
Now you have successfully prepared a 10mM NaH2PO4 solution!