Player B longest home run distance is 500 feet there are 5280 feet in one mile how many home runs will player B need to hit at his longest distance for the total to be greater than 1 mile
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Player B’s longest home run distance is 500 ft.
There are 5,280 ft in 1 mi. How many home
runs would Player B need to hit at his longest
distance for the total to be greater than 1 mi?
To determine the number of home runs Player B needs to hit at his longest distance for the total to be greater than 1 mile, we'll convert the distance into miles.
Given that there are 5280 feet in one mile and Player B's longest home run distance is 500 feet, we can find out the distance in miles by dividing 500 by 5280:
500 feet ÷ 5280 feet/mile ≈ 0.0947 miles.
Now, we need to find the number of home runs required for the total distance to surpass 1 mile. Let's assume each home run adds the same distance to the total.
We can divide 1 mile by the converted distance of a single home run:
1 mile ÷ 0.0947 miles/home run ≈ 10.56 home runs.
Player B will need to hit at least 11 home runs at his longest distance for the total distance covered to be greater than 1 mile.