In an examination 80% candidates passed in English and 85% candidates passed in Mathematics. If 73% candidates passed in both these subjects, then what per cent of candidates failed in both the subjects?

100-(80+85-73) = 8

To find out the percentage of candidates who failed in both English and Mathematics, we need to first determine the percentage of candidates who passed in at least one subject.

Let's assume there are 100 candidates in total.

Since 80% of candidates passed in English, the number of candidates who passed in English is (80/100) * 100 = 80.

Similarly, since 85% of candidates passed in Mathematics, the number of candidates who passed in Mathematics is (85/100) * 100 = 85.

Now, since 73% of candidates passed in both subjects, the number of candidates who passed in both English and Mathematics is (73/100) * 100 = 73.

To find the number of candidates who passed in at least one subject, we need to add the number of candidates who passed in English and Mathematics and subtract the number of candidates who passed in both subjects:

Number of candidates who passed in at least one subject = Number of candidates who passed in English + Number of candidates who passed in Mathematics - Number of candidates who passed in both English and Mathematics

= 80 + 85 - 73 = 92.

Therefore, the number of candidates who failed in both subjects is the difference between the total number of candidates (100) and the number of candidates who passed in at least one subject:

Number of candidates who failed in both subjects = Total number of candidates - Number of candidates who passed in at least one subject

= 100 - 92 = 8.

Hence, 8% of candidates failed in both English and Mathematics.