four capacitors of 2uf are connected in series the equivalent capacitance is
4 (1 / 2 μf) = 1 / Ce
Ce = 2 μf / 4
To find the equivalent capacitance of capacitors connected in series, you need to use the following formula:
1/Ceq = 1/C1 + 1/C2 + 1/C3 + ...
In this case, you have four capacitors of 2μF connected in series. Plugging in the values into the formula:
1/Ceq = 1/2μF + 1/2μF + 1/2μF + 1/2μF
Simplifying the equation:
1/Ceq = 4/2μF
Inverting both sides of the equation:
Ceq = 2μF/4
Simplifying further:
Ceq = 0.5μF
Therefore, the equivalent capacitance of the four 2μF capacitors connected in series is 0.5μF.
To find the equivalent capacitance of capacitors connected in series, you need to use the formula:
1/Ceq = 1/C1 + 1/C2 + 1/C3 + ...
In this case, you have four capacitors of 2μF each connected in series. So the equation becomes:
1/Ceq = 1/2μF + 1/2μF + 1/2μF + 1/2μF
Now, let's simplify this equation:
1/Ceq = (1 + 1 + 1 + 1)/2μF
1/Ceq = 4/2μF
1/Ceq = 2/μF
To find the equivalent capacitance, we need to take the reciprocal of both sides of the equation:
Ceq = 1/(2/μF)
Ceq = μF/2
Therefore, the equivalent capacitance of four capacitors of 2μF connected in series is 1μF.