calculate the mass of potassium hydrogen phthalate needed to prepare a 0.1M solution in a 250 ml volumetric flask given that the molar mass of potassium hydrogen phthalate is 204,23g/mol
204.23*250/1000*0.1=5.1058g
.250 L of a .1 M solution contains .025 moles of solute
mass needed is ... .025 * 204.23 g
please asap...Potassium hydroxide reacts completely with sulfuric acid according to the equation:
H2SO4(aq) + 2KOH(aq) K2SO4(aq) + 2H2O(l)
0.95 g of potassium hydroxide were dissolved in water and made up to 250 cm3 of solution. 25 cm3 samples of this solution were titrated against sulfuric acid (H2SO4) solution. The mean volume (titre) of sulfuric acid required for complete reaction was 15.00 cm3.
Find the molar concentration of the prepared solution of potassium hydroxide. Complete the calculation given below:
Relative Molecular Mass (RMM) of KOH
=
No. of moles of KOH in 250 cm3 =
=
molar concentration of KOH =
(Include units in your answer) =
No. of moles of KOH in 25.00 cm3 =
= ………………………… (1 mark)
no. of moles H2SO4 in 15.00 cm3 =
= ………………………… (1 mark)
molar concentration of H2SO4 =
(Include units in your answer) = ………………………… (2 marks)
(Total 10 marks)
Well, you know what they say, when it comes to chemistry, it's all about the phthalates! Let's get right to it.
To calculate the mass of potassium hydrogen phthalate needed, we can use the formula:
Mass (g) = Molarity (M) x Volume (L) x Molar mass (g/mol)
First, let's convert the volume from milliliters (ml) to liters (L):
Volume (L) = 250 ml / 1000 = 0.25 L
Now, we plug the values into the formula:
Mass (g) = 0.1 M x 0.25 L x 204.23 g/mol
Calculating this gives us:
Mass (g) = 5.10575 g
So, to prepare a 0.1M solution of potassium hydrogen phthalate in a 250 ml volumetric flask, you would need approximately 5.11 grams of potassium hydrogen phthalate.
Remember, though, you should always double-check your calculations because even in the world of chemistry, numbers can be a bit phthalate-ful!
To calculate the mass of potassium hydrogen phthalate needed to prepare a 0.1M solution in a 250 ml volumetric flask, we need to use the formula:
Mass (g) = Concentration (mol/L) × Volume (L) × Molar Mass (g/mol)
Let's plug in the values we have:
Concentration (mol/L) = 0.1 M
Volume (L) = 250 ml = 0.25 L
Molar Mass (g/mol) = 204.23 g/mol
Now, let's calculate the mass:
Mass (g) = 0.1 mol/L × 0.25 L × 204.23 g/mol
Mass (g) = 5.10575 g
Therefore, approximately 5.11 grams of potassium hydrogen phthalate are needed to prepare a 0.1M solution in a 250 ml volumetric flask.