The gas in a cylinder has a volume of 8 liters at a pressure of 108 kPa. The pressure of the gas is increased to 224 kPa. Assuming the temperature remains constant, what would the new volume be?: _______L
How would I go about solving this particular problem?
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volume is inversely related to pressure (Boyle's Law)
P1*V1 = P2*V2
108 * 8 = 224 * V2
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To solve this problem, you can use the combined gas law equation, which relates the pressure, volume, and temperature of a gas. The formula is:
(P1 * V1) / T1 = (P2 * V2) / T2
In this case, the temperature remains constant, so T1 = T2.
Let's break down the problem step by step:
1. Identify the known values:
- Initial volume (V1) = 8 liters
- Initial pressure (P1) = 108 kPa
- Final pressure (P2) = 224 kPa
2. Plug in the known values into the formula:
(P1 * V1) / T1 = (P2 * V2) / T2
(108 kPa * 8 L) / T1 = (224 kPa * V2) / T2
3. Since the temperature remains constant, T1 = T2, resulting in:
(108 kPa * 8 L) / T = (224 kPa * V2) / T
4. Cross-multiply and solve for V2:
(108 kPa * 8 L) = (224 kPa * V2)
Divide both sides by 224 kPa:
(108 kPa * 8 L) / 224 kPa = V2
5. Calculate the new volume:
(108 * 8) / 224 = V2
V2 = 3.857 L
Therefore, the new volume would be approximately 3.857 Liters when the pressure is increased to 224 kPa, assuming the temperature remains constant.