Two RSM students are standing 20ft apart and spot Mrs Rifkin. If they immediately run opposite direction with speeds of 300 ft/min and 200 ft/min, how many hours will pass until they are 3,000 ft apart?
Their combined speeds are 500 meters per minute, but they're 20 feet apart first, so you should multiply 500 by 5 and add 20 (because it's the distance they are apart from each other before they spot Mrs. Rifkin)
5*500+20=2520 (Note: if you did 6 times 500, then it would be 3000, and that's over 3000 if you add the original 20)
So now, subtract 2520 from 3000.
3000-2520=480
Now figure out how much time it takes them to go 480 meters then add the time (in MINUTES!) to 5 minutes because that's how we got 2500 meters.
Your answer should be 5 and ___ minutes.
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To find out how many hours will pass until they are 3,000 ft apart, we first need to determine how fast the distance between them is changing.
The student who is running at 300 ft/min is increasing the distance between them at a rate of 300 ft/min, while the student who is running at 200 ft/min is decreasing the distance between them at a rate of 200 ft/min.
So, the distance between them is changing at a rate of 300 ft/min + 200 ft/min = 500 ft/min.
To find out how long it will take to be 3,000 ft apart, we can divide the distance (3,000 ft) by the rate of change (500 ft/min):
3,000 ft / 500 ft/min = 6 min.
Therefore, it will take 6 minutes for the two students to be 3,000 ft apart.
To find out how many hours will pass until the two RSM students are 3,000 ft apart, we can use the concept of relative motion.
Let's assume that the two RSM students start moving in opposite directions at the same time when they spot Mrs. Rifkin.
The relative speed between the two students is the sum of their individual speeds: 300 ft/min + 200 ft/min = 500 ft/min.
Since they are initially 20 ft apart, they need to cover an additional distance of 3,000 ft - 20 ft = 2,980 ft to reach a total distance of 3,000 ft between them.
To determine how long it takes in hours, we can use the formula: Time = Distance / Speed.
Time = 2,980 ft / 500 ft/min = 5.96 min.
Since there are 60 minutes in an hour, 5.96 min is approximately 0.0993 hours.
Therefore, it will take approximately 0.0993 hours (or about 5 minutes and 58 seconds) for the two RSM students to be 3,000 ft apart.
They would be separating at 500 ft/min
time to go 3000 ft at that speed
= 3000/500 min
or
= 6 minutes
or
time taken --- x minutes
distance of one student = 300x
distance of other student = 200x
300x + 200x = 3000
500x = 3000
x = 6 , just like above.