# Calculus

posted by andre

Calculate the interval of convergence.
Sigma from n=1 to infinity of (n!*x^n)/n^n.

1. Steve

try using the ratio test. You should be able to show that the series converges for |x| < e

2. andre

I tried and I got
|x|lim n-infinity of |(n/n+1)^n|
which I get |x|<1

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