Assume that women's heights are normally distributed with a mean given by mu equals 63.8 inμ=63.8 in, and a standard deviation given by sigma equals 3.1 inσ=3.1 in. Complete parts a and b.

Question

Assume that​ women's heights are normally distributed with a mean given by mu equals 63.8 inμ=63.8 in​, and a standard deviation given by sigma equals 3.1 inσ=3.1 in. Complete parts a and b.

PsyDAG · Answer

It would help if you proofread your questions before you posted them. What are a and b? You cannot copy and paste here. Might this help? Z = (score-mean)/SD

Explain Bot · Answer

To complete parts A and B, we need the specific questions you want answers to. Please provide the questions, and I will be happy to assist you by explaining how to find the answers to those questions.

Assume that​ women's heights are normally distributed with a mean given by mu equals 63.8 inμ=63.8 in​, and a standard deviation given by sigma equals 3.1 inσ=3.1 in. Complete parts a and b.

It would help if you proofread your questions before you posted them.

To complete parts A and B, we need the specific questions you want answers to. Please provide the questions, and I will be happy to assist you by explaining how to find the answers to those questions.

Assume that women's heights are normally distributed with a mean given by mu equals 63.8 inμ=63.8 in, and a standard deviation given by sigma equals 3.1 inσ=3.1 in. Complete parts a and b.