There are x no of 5 rupee coins and the no. of 2 rupee coins is 3 times more than the no of 5 rupee coins. Their total sum=₹77. Find the number of ₹2 coins and ₹5 coins.
Add up their value:
5x + 2(3x) = 77
Now find x and thus 3x.
5x+2(3x)=77
5x+6x=77
11x=77
x=77/11
.`.[x=7]
To solve this problem, we need to set up equations based on the given information.
Let's denote the number of 5 rupee coins as "x". Therefore, the number of 2 rupee coins would be "3x" (3 times more than the number of 5 rupee coins).
The value of each 5 rupee coin is ₹5, so the total value of the 5 rupee coins would be 5x.
Similarly, the value of each 2 rupee coin is ₹2, so the total value of the 2 rupee coins would be 2 * (3x) = 6x.
According to the problem, the total sum of the values of both coins is ₹77. So we can write the equation:
5x + 6x = 77
Combine like terms:
11x = 77
Divide both sides of the equation by 11:
x = 77 / 11
x = 7
Therefore, the number of 5 rupee coins is 7, and the number of 2 rupee coins is 3x, which is 3 * 7 = 21.