When a body hanging form a spring balance is immersed in water it floats just below the surface of water and shows 100 g loss in its water ? (1) what is the weight of the body in water? (2) what is the weight of the body in air? (3) what is the upthrust on the body? (4) what is the volume of the body? Give reason for your answers. Give: acceleration due to gravity at the place is 10 m s -2, volume of 1 g of water = 1 mL
density of water = 1 gram/cm^3
1. weight in water is 0
2.volume = 100 cm^3 because it displaced 100 grams of water
Therefore if neutrally buoyant it weights 100 grams in air.
3. Buoyant force = 100 grams . That was given.
4. volume = 100 cm^2 as we said
To answer the questions, we need to analyze the scenario and use relevant equations and principles from physics. Here are the steps to find the answers:
1) Weight of the body in water: When a body is partially or fully submerged in water, it experiences an upward force known as buoyancy or upthrust. This force is equal to the weight of the water displaced by the submerged object.
The body floats just below the surface of water, indicating that the buoyant force and the weight of the body are balanced. Therefore, the weight of the body in water is equal to the buoyant force acting on it.
2) Weight of the body in air: The weight of the body in air can be determined by finding the difference between its weight in air and its weight loss in water. Since the body shows a 100 g loss in water, we can say that its weight loss in water is 100 g.
3) Upthrust on the body: The upthrust on the body is the buoyant force acting on it when it is submerged. This force is equal to the weight of the water displaced by the body.
To determine the upthrust, we need to calculate the weight of the water displaced by the body, which is equal to the weight loss of the body in water (from question 1).
4) Volume of the body: The volume of the body can be calculated using the fact that the weight of 1 g of water is equal to its volume in milliliters (mL).
Since the body loses 100 g in water, we can infer that its volume is 100 mL (since 1 g = 1 mL for water).
Therefore, the answers are as follows:
(1) Weight of the body in water = weight loss in water = 100 g
(2) Weight of the body in air = weight in water + weight loss in water = weight in water + 100 g
(3) Upthrust on the body = weight of water displaced = weight loss in water = 100 g
(4) Volume of the body = weight loss in water = 100 mL (since 1 g = 1 mL for water)