If p^1/3 = (8x)^1/6, x^-1/2 =4^-1/4, and 4y = |p-8|, what is the value of y?
Looks like Benjamin to me, but do it the same way:
p^1/3 = (8x)^1/6
p^2 = 8x
x^-1/2 = 4^-1/4
x^-2/4 = 4^-1/4
x^-2 = 4^-1
x^2 = 4
x = 2
p^2 = 16
4y = |p-8|
4y = 8
y = 2