A bomber is flying horizontally with velocity of 540 km/hr at height 2000 m .How far the enemy camp should it release a bomb so as to hit the camp.
To calculate the distance the bomber should release the bomb from the enemy camp, we need to consider the horizontal velocity of the bomber, the height at which it is flying, and the acceleration due to gravity.
Let's break it down step by step:
Step 1: Convert the horizontal velocity from km/hr to m/s.
- 540 km/hr = (540 * 1000) / 3600 m/s = 150 m/s
Step 2: Determine the time it takes for the bomb to reach the ground.
- When the bomb is released, it will follow a projectile motion path. In this case, we assume that the initial vertical velocity is 0 m/s.
- The equation for the height of a projectile launched vertically is h = (1/2) * g * t^2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time.
- In this case, h = 2000 m, so we can rearrange the equation to solve for t: t = sqrt(2h / g)
- t = sqrt(2 * 2000 / 9.8) = 20.20 seconds (approximately)
Step 3: Calculate the horizontal distance traveled by the bomber in that time.
- The horizontal distance equals the horizontal velocity multiplied by the time: distance = velocity * time
- distance = 150 m/s * 20.20 s = 3030 meters
Therefore, the bomber should release the bomb approximately 3030 meters away from the enemy camp in order to hit the camp.
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just figure how long it takes to fall, then calculate the distance flown in that time.