A quiz consists of 90 multiple-choice questions, each with 4 possible answers (A, B, C and D). For someone who makes random guess , A is the correct answer for all the questions. If each right answer carries 4 marks and each wrong answer gives -1/4 marks, what probable marks someone will get? Please give calculation
Seems like he'll get 1/4 of them right, and 3/4 of them wrong. So, I'd expect a score of
90*(1/4)*4 + 90*(3/4)(-1/4)
This is the FOURTH time ANUP has asked this question.
How many different answers does he/she need??
I guess we'll just keep seeing the question until
(a) an answer appears that he likes
(b) the assignment is due
(c) he posts his own solution
LOL! You're probably right!
To calculate the probable marks someone will get under these conditions, we need to consider the total number of questions, the number of correct answers, and the marking scheme.
Given that the quiz consists of 90 multiple-choice questions and that the person is making random guesses with answer "A" for all the questions, we can conclude that all of their answers will be correct. Therefore, the number of correct answers is equal to the total number of questions, which is 90.
Next, we need to determine the marking scheme. Each correct answer carries 4 marks, while each wrong answer deducts 1/4 marks.
Calculating the probable marks:
Marks for correct answers: 90 questions × 4 marks = 360 marks
Since the person is making random guesses and each guess is correct, there are no wrong answers. Therefore, there will be no deductions for wrong answers.
In conclusion, the person will probably receive 360 marks.