The sum of a two digit number is 8 .The digit in the units palce is1

more than six times the digit in tens place .Find the number

The tens digit must be 1.

6 * 1 = 6
6 + 1 = 7

17

To find the two-digit number that satisfies the given conditions, we need to break down the information provided and solve step by step.

Let's assume the digit in the tens place is 'x' and the digit in the units (ones) place is 'y'.

According to the problem statement:
1. The sum of the digits is 8, which gives us the equation: x + y = 8.

2. The digit in the units place is 1 more than six times the digit in the tens place, which gives us the equation: y = 6x + 1.

Now, we can solve the equations simultaneously to find the values of 'x' and 'y'.

Substitute the value of 'y' from equation 2 into equation 1:
x + (6x + 1) = 8.

By simplifying the equation:
7x + 1 = 8,
7x = 8 - 1,
7x = 7.

Divide both sides of the equation by 7:
x = 1.

Substitute the value of 'x' into equation 1 to find 'y':
1 + y = 8,
y = 8 - 1,
y = 7.

Therefore, the number is 17, where '1' is the digit in the tens place and '7' is the digit in the units place.

So, the two-digit number that satisfies the given conditions is 17.

Unit place=y

Tenth place=x
The number=10x+y
For x+y=9 & y=3x+1
Solving the equation and number =27