A child pulls a wagon with a force of 58 N by a handle making an angle of 27 degrees with the horizontal. If the wagon has a mass of 4.5 kg, to the nearest hundredth of a m/s2 what is the acceleration of the wagon
the horizontal force is
58 cos27°
F = ma
so, plug in your numbers and solve for a.
.27
To find the acceleration of the wagon, we will first resolve the force vector into its horizontal and vertical components.
The horizontal component of the force can be calculated using the formula:
F(horizontal) = F × cos(θ)
Where:
F(horizontal) is the horizontal component of the force
F is the total force exerted (58 N in this case)
θ is the angle between the force and the horizontal (27 degrees in this case)
Substituting the given values into the formula:
F(horizontal) = 58 N × cos(27°)
Next, we can use Newton's second law of motion to find the acceleration of the wagon:
F(horizontal) = mass × acceleration
Rearranging the formula to solve for acceleration:
acceleration = F(horizontal) / mass
Now, let's plug in the values:
acceleration = (58 N × cos(27°)) / 4.5 kg
To calculate the final answer to the nearest hundredth of a m/s², perform the calculation and round the result.